(a) Rs 4096
A = Rs 4913, n = 3, r = 6\(\frac{1}{4}\)% = \(\frac{25}{4}\)%, P = ?
\(\therefore\) 4913 = P\(\big(1+\frac{25}{400}\big)^3\) \(\Rightarrow\) 4913 = P\(\big(1+\frac{1}{16}\big)^3\)
\(\Rightarrow\) 4913 =P\(\big(\frac{17}{16}\big)^3\) \(\Rightarrow\) 4913 = P x \(\frac{4913}{4096}\)
\(\Rightarrow\) P = Rs 4096