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Find x, if 8x–2 \(\big(\frac12\big)^{4-3x}\) = (0.0625)x

(a) 0 

(b) 4 

(c) 2 

(d) 1

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(d) 1

 8x–2 \(\big(\frac12\big)^{4-3x}\) = (0.0625)x 

(23)x – 2 x (2–1)4–3x = \(\big(\frac{625}{10000}\big)^x\) 

⇒ 23x-6 x 2-4+3x\(\big(\frac{1}{16}\big)^x\) = (2-4)x = 2-4x

⇒ 23x-6-4+3x = 2-4x

⇒ 26x – 10 = 2– 4x 

⇒ 6x – 10 = – 4x 

⇒ 10x = 10 ⇒ x = 1.

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