(d) 1
8x–2 x \(\big(\frac12\big)^{4-3x}\) = (0.0625)x
(23)x – 2 x (2–1)4–3x = \(\big(\frac{625}{10000}\big)^x\)
⇒ 23x-6 x 2-4+3x = \(\big(\frac{1}{16}\big)^x\) = (2-4)x = 2-4x
⇒ 23x-6-4+3x = 2-4x
⇒ 26x – 10 = 2– 4x
⇒ 6x – 10 = – 4x
⇒ 10x = 10 ⇒ x = 1.