(b) Rs 1690
Since the man repays Rs 1500 at the end of each year
\(\therefore\) Amount he owes at the end of 1st year = 5000\(\big(1+\frac{10}{100}\big)\) - 1500
= 5500-1500 = Rs 4000
Amount he owes at the end of 2nd year
= 4000\(\big(1+\frac{10}{100}\big)\)- 1500
= 4000 - 1500= Rs 2900
Amount he owes at the end of 3rd year
= 2900\(\big(1+\frac{10}{100}\big)\)- 1500
= 3190 – 1500 = Rs 1690