Question

Find the distance between the points (a cos 60°, 0) and (0, a sin 60°).

Answer 1

Required distance = \(\sqrt{(0-a\,cos 60°)^2+(a\, sin\,60°-0)^2}\)

= \(\sqrt{\big(\frac{-a}{2}\big)^2+\big(\frac{\sqrt3a}{2}\big)^2}\)

= \(\sqrt{\frac{a^2}{4}+\frac{3a^2}{4}}=\sqrt{\frac{4a^2}{4}}\) = a units.