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in Coordinate Geometry by (49.3k points)
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Find a point on the x-axis, which is equidistant from the points (7, 6) and (–3, 4).

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Any point on the x-axis is (x, 0) 

According to the given condition, 

Distance between (x, 0) and (7, 6) = Distance between (x, 0) and (–3, 4)

⇒ \(\sqrt{(x-4)^2+(0-6)^2}\) = \(\sqrt{(x-3)^2+(0-4)^2}\)

⇒ \(\sqrt{x^2-14x+49+36}\) = \(\sqrt{x^2-6x+9+16}\)

⇒ x2 – 14 x + 85 = x2 + 6x + 25 ⇒ 60 = 20x ⇒ x = 3

∴ The required point is (3, 0).

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