(a) 25000
Let the number of bushes in the beginning be x
Then, 26730 = x\(\big(1+\frac{10}{100}\big)\)\(\big(1+\frac{8}{100}\big)\)\(\big(1-\frac{10}{100}\big)\)
\(\Rightarrow\)26730 = x x \(\frac{11}{10}\) x \(\frac{27}{25}\) x \(\frac{9}{10}\)
\(\Rightarrow\) x = \(\frac{26730\times 10\times 25 \times10}{11\times9\times27}\)
\(\Rightarrow\)x = 25000.