Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
755 views
in Coordinate Geometry by (49.2k points)
closed by

The co-ordinates of the vertices of a side of square are (4, –3) and (–1, –5). Its area is

(a) 2 √29 sq. units 

(b) \(\frac{\sqrt{89}}{2}\) sq. units 

(c) 89 sq. units 

(d) 29 sq. units

1 Answer

+1 vote
by (46.2k points)
selected by
 
Best answer

(d) 29 sq. units

Length of a side of the square 

\(\sqrt{(-1-4)^2+(-5+3)^2}\)

\(\sqrt{25+4} = \sqrt{29}\) units.

∴ Area = (Side)2\((\sqrt{29})^2\) sq. units

= 29 sq. units

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...