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Find the solution set of the system of equations:  \(\frac{4}{X}\) + 5y = 7 and \(\frac{3}{X}\) + 4y = 5.

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Let \(\frac{1}{X}\) = a. Then the system of equations become

4a + 5y = 7.........(i)

3a + 4y = 5............(ii)

Multiplying equation (1) by 3 and equation (2) by 4 and subtracting equation (2) from equation (1), we get

\(\Rightarrow\) Putting y = –1 in (1), we get

4a – 5 = 7 \(\Rightarrow\) 4a = 12 \(\Rightarrow\) a = 3 \(\Rightarrow\) x = \(\frac{1}{3}\)

\(\therefore\) The solution set is \(\big(\frac{1}{3},-1\big)\).

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