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0 votes
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in Coordinate Geometry by (49.2k points)

The point on the x-axis which is equidistant from the points (7, 6) and (–3, 4) is 

(a) (0, 3) 

(b) (3, 0) 

(c) (–3, 0) 

(d) (0, –3)

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1 Answer

+1 vote
by (46.1k points)

(b) (3,0)

Let a point on the x-axis be (a, 0) . Then, 

Dist. bet. (a, 0) and (7, 6)  = Dist. bet. (a, 0) and (–3, 4) 

(7 – a)2 + (6 –0)2 = (–3 – a)2 + (4 – 0)2 

Now solve.

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