Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
2.3k views
in Matrices and Determinants by (47.4k points)
closed by

If A = \( \begin{bmatrix} a&b\\c&d \end{bmatrix}\) such that ad – bc ≠ 0 then A-1 is:

(a) \(\frac{1}{ad-bc} \begin{bmatrix} d&b\\-c&a \end{bmatrix}\)

(b) \(\frac{1}{ad-bc} \begin{bmatrix} d&b\\c&a \end{bmatrix}\)

(c) \(\frac{1}{ad-bc} \begin{bmatrix} d&-b\\-c&a \end{bmatrix}\)

(d) \(\frac{1}{ad-bc} \begin{bmatrix} d&-b\\c&a \end{bmatrix}\)

1 Answer

+1 vote
by (47.8k points)
selected by
 
Best answer

(c) \(\frac{1}{ad-bc} \begin{bmatrix} d&-b\\-c&a \end{bmatrix}\)

A = \( \begin{bmatrix} a&b\\c&d \end{bmatrix}\)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...