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0 votes
1.0k views
in Matrices and Determinants by (47.4k points)

Which of the following matrix has no inverse?

(a) \( \begin{pmatrix} -1&1\\1&-4 \end{pmatrix}\)

(b) \( \begin{pmatrix} 2&-1\\-4&2 \end{pmatrix}\)

(c) \( \begin{pmatrix} cos\,a&sin\,a\\-sin\,a&cos\,a \end{pmatrix}\)

(d) \( \begin{pmatrix} sin\,a&sin\,a\\-cos\,a&cos\,a \end{pmatrix}\)

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1 Answer

+1 vote
by (47.8k points)

(b) \( \begin{pmatrix} 2&-1\\-4&2 \end{pmatrix}\)

So \( \begin{pmatrix} 2&-1\\-4&2 \end{pmatrix}\) has no inverse.

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