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0 votes
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in Matrices and Determinants by (47.4k points)
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Inverse of \( \begin{pmatrix} 3&1\\5&2 \end{pmatrix}\) is:

(a) \( \begin{pmatrix} 2&-1\\-5&3 \end{pmatrix}\)

(b) \( \begin{pmatrix} -2&5\\1&-3 \end{pmatrix}\)

(c) \( \begin{pmatrix} 3&-1\\-5&-3 \end{pmatrix}\)

(d) \( \begin{pmatrix} -3&5\\1&-2 \end{pmatrix}\)

1 Answer

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Best answer

(a) \( \begin{pmatrix} 2&-1\\-5&3 \end{pmatrix}\)

Let A = \( \begin{pmatrix} 3&1\\5&2 \end{pmatrix}\)    

|A| = [6 – 5] = 1

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