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The average of two numbers is 6 and four times the difference between them is 16. Find the numbers.

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Let the numbers be x and y. Given,

\(\frac{X+Y}{2}\)= 6  \(\Rightarrow\) x + y = 12

4 (x – y) = 16 \(\Rightarrow\) 4x – 4y = 16

Multiplying equation (1) by 4 and adding to equation (2), we get


\(\Rightarrow\) x = \(\frac{64}{8}\)= 8

Putting x = 8 in (1), we get

8 + y = 12

\(\Rightarrow\) y = 12 – 8 = 4

\(\therefore\) The numbers are 8 and 4.

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