Let the given fraction be \(\frac{X}{y}\).Then,
\(\frac{X+2}{y+1}\)= \(\frac{1}{2}\) \(\Rightarrow\) 2x + 4 =y + 1 \(\Rightarrow\) 2x – y = – 3 ..........(i)
\(\frac{X+1}{y-2}\) = \(\frac{3}{5}\) \(\Rightarrow\) 5x + 5 = 3y - 6 \(\Rightarrow\) 5x – 3y = –11 ..........(ii)
Now,
Putting x = 2 in equation (1), we get
4 – y = – 3 \(\Rightarrow\) – y = – 3 – 4 \(\Rightarrow\) y = 7
\(\therefore\) The given fraction is \(\frac{2}{7}\)