Let H be the cost of a horse and C the cost of a cow.
Then, 4H + 9C = 13400
Also, \(\frac{10}{100}\) x 4H + \(\frac{20}{100}\) x 9C =1880
\(\Rightarrow\)4H + 18C = 18800
Subtracting equation (1) from equation (2), we get
9C = 5400 \(\Rightarrow\) C = \(\frac{5400}{9}\) = 600
Putting C = 600 in (1), we get
4H + 9 × 600 = 13400 \(\Rightarrow\) 4H = 8000 \(\Rightarrow\) H = \(\frac{8000}{4}\) = 2000
\(\therefore\) The cost of a horse is Rs 2000.