Question

The course of an enemy submarine as plotted on a set of rectangular axes is 2x + 3y = 5. On the same axes the course of the destroyer is indicated by x – y = 10. The point (x, y) at which the submarine can be destroyed is : 

(a) (–7, 3) 

(b) (–3, 7) 

(c) (3, –7) 

(d) (7, –3)

Answer 1

(d) (7, –3)

x – y = 10

\(\Rightarrow\) x = y + 10

Substitute this value of x in eqn 2x + 3y = 5.

so, that we get the solution.