(c) –6 and 8
(x + 3)(y – 5) = xy + 39
\(\Rightarrow\) xy + 3y – 5x – 15 = xy + 39
\(\Rightarrow\) –5x + 3y = 54 5x – 3y = –54 ..........(i)
(x – 2) (y + 3) = xy – 40
\(\Rightarrow\) xy – 2y + 3x – 6 = xy – 40
\(\Rightarrow\) –2y + 3x = –34 \(\Rightarrow\) 3x – 2y = – 34 .............(ii)
Multiply (i) by 3 and (ii) by 5 and then subtract eqn (ii) from eqn (i).
so that we get solution.