(b) Rs 35
Let the cost of one apple and one orange be Rs x
and Rs y respectively.
Then, according to the given question,
8x + 5y = 92 ........(i)
5x + 8y = 77 .........(ii)
Multiplying eqn (i) by 5 and eqn (ii) by 8, we get
40x + 25y = 460 ….....(iii)
40x + 64y = 616 …....(iv)
Subtracting eqn (iii) from eqn (iv),
39y = 156
\(\Rightarrow\) y = \(\frac{156}{39}\) = 4
From (i) putting the value of y, we get
8x + 20 = 92
\(\Rightarrow\) 8x = 72 \(\Rightarrow\)x = 9
\(\therefore\) Cost of 2 oranges and 3 apples
= 2 × Rs 4 + 3 × Rs 9 = Rs 8 + Rs 27 = Rs 35.