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The lateral surface area of a hollow cylinder is 5632 cm2. It is cut along its height and a rectangular sheet of width 44 cm is formed. Find the perimeter of the rectangular sheet?

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Since the cylinder is cut along its height, the circumference of its base (or top) = width of rectangular sheet, i.e., 2πr = 44 

cm Given 2 5632

⇒ h = \(\frac{5632}{44}\) cm = 128 cm

∴ Required perimeter = 2(l + b) 

= 2(128 + 44) cm = 344 cm.

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