Question

Find the 26th term of the A.P: 10, 6, 2, –2, – 6, –10, ..... ?

(a) –86 

(b) 96 

(c) –90 

(d) –106

Answer 1

Answer : (c) - 90

 T_n = a + (n – 1)d 

⇒ T₂₆ = a + 25d 

Here a = 10, d = – 4 

∴ T₂₆ = 10 + 25 × (–4) 

= 10 – 100 

= – 90.