Question

Entry fee in an exhibition was Re 1. Later this was reduced by 25% which increased the sale by 20%. Find the percentage increase in the number of visitors

Answer 1

Let the number of visitors be x. Then, as entry fee = Re 1, Sale = x × Re 1 = Re x

Reduced entry fee = Re 0.75, Increased sale = x + 20% of x = Rs 1.2 x

Then, increased number of visitors = \(\frac{Rs\,1.2X}{Re\,0.75}\) = 1.6x

\(\therefore\) % increase = \(\Big(\frac{(1.6X-X)}{X}\times100\Big)\)% = (0.6 × 100)% = 60%.