Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
954 views
in Arithmetic Progression by (22.8k points)
closed by

If a, b, c be in Arithmetic Progression, then the value of (a + 2b – c) (2b + c – a) (a + 2b + c) is

(a) 3abc 

(b) 4abc 

(c) 8abc 

(d) 16abc

1 Answer

+1 vote
by (23.7k points)
selected by
 
Best answer

Answer : (d) 16abc

a, b, c are in A.P. ⇒ 2b = a + c 

∴ (a + 2b – c) (2b + c – a) (a + 2b + c)  

= (a + a + c – c) (a + c + c – a) (2b + 2b) 

= 2a · 2c · 4b 

= 16abc.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...