(d) 25%
Let the maximum marks be M. Then, Pass marks = 20% of M + 30 = 32% of M – 42
\(\Rightarrow\) 12% of M = 72 \(\Rightarrow\) M = \(\frac{72\times100}{12}\) = 600
\(\therefore\) Pass marks = 20% of 600 + 30 = 150
\(\Rightarrow\) Percentage of pass marks = \(\frac{150}{600}\) x 100%
= 25%