(d) 80 min
Volume of the tank = πr2h = π x (10)2 x 15 = 1500π m3
Area of the pipe = \(\frac{πD^2}{4}=\frac{π\times(0.05)^2}{4} = \frac{π}{16}\) m2
Rate of flow of water in the pipe
= Area × Velocity = \(\frac{π}{16}\times5=\frac{5π}{16}\) m3/s
∴ Time required to fill the tank = \(\frac{1500π}{\frac{5π}{16}}\) seconds
= 4800 seconds = \(\frac{4800}{60}\) min = 80 min.