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in Arithmetic Progression by (22.8k points)
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What is the sum of numbers lying between 107 and 253, which are divisible by 5?

(a) 5250 

(b) 5210 

(c) 5220 

(d) 5000

1 Answer

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Answer : (c) 5220

The numbers between 107 and 253 divisible by 5 are  

110, 115, 120, .......... , 245, 250. 

This is an A.P with first term (a) = 110 and common difference (d) = 5. 

Let the last term be the nth term.

∴ Tn = a + (n – 1)d 

⇒ 110 + (n – 1) × 5 = 250 

⇒ 5n = 250 – 105 = 145 

⇒ n = 29.

∴ Required sum = \(\frac{n}{2}\) (a + Tn) = \(\frac{29}{2}\)(110 + 250)

\(\frac{29}{2}\) × 360 = 5220

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