(c) Rs 2025
Let the original bus fare per person be Rs x,
daily passenger traffic be y.
Daily collection at the depot = Rs xy
Increased bus fare = Rs 1.2x,
Reduced passenger traffic = 0.9y
Daily collection at the depot = Rs 1.2x × 0.9y
= 1.08xy
Given, 1.08xy = xy + 150 \(\Rightarrow\) xy = \(\frac{150}{0.08}\) = 1875
\(\therefore\) Increased daily collection = Rs 1875 + Rs 150 = Rs 2025.