Question

In an examination in which full marks were 800, A gets 20% more than B, B gets 20% more than C, and C gets 15% less than D. If A got 576, what percentage of full marks did D get (approximately) ? 

(a) 45.7 

(b) 51.2 

(c) 58.8 

(d) 61.7

Answer 1

(c) 58.8

A = \(\frac{120}{100}\)B, B = \(\frac{120}{100}\)C, C = \(\frac{85}{100}\)D

\(\Rightarrow\) B = \(\frac{5}{6}\)A, C = \(\frac{5}{6}\)B, D= \(\frac{20}{17}\)D

\(\therefore\) B = \(\frac{5}{6}\)x 576 = 480;  C = \(\frac{5}{6}\) x 480 = 400;

D = \(\frac{20}{17}\) x 400 = \(\frac{8000}{17}\)

So, required percentage = \(\big(\frac{8000}{17}\times\frac{1}{800}\times100\big)\)%

= 58.82%