(a) 120
Here there are 6 letters.
The letter C occurs one time
The letter H occurs one time
The letter E occurs three times
The letter S occurs one time
Number of arrangements = \(\frac{6!}{1!1!3!1!}=\frac{6!}{3!}\)
= \(\frac{6\times5\times4\times3!}{3!}\) = 120