Let Delhi – Ghaziabad distance be a km. Then,
Speed of train X = a km/hr
Speed of train Y = \(\frac{a}{\frac{3}{2}}\) km/hr = \(\frac{2a}{3}\) km/hr
Suppose they meet after b hours, then \(ab + \frac{2ab}{3} =a ⇒\frac{5b}{3}=1⇒b=\frac35\) hrs = 36 minutes
∴ They meet at 4 : 36 pm.