(d) 250 m
Distance travelled by the 1st car in 15 seconds
= OA = \(\bigg(36\times\frac{5}{18}\bigg)\)x 15 m = 150 m
Distance travelled by the 2nd car in 15 seconds
= OB = \(\bigg(48\times\frac{5}{18}\bigg)\)x 15 m = 200 m
∴ Distance between them after 15 seconds
= AB = \(\sqrt{OA^2+OB^2} = \sqrt{150^2+200^2}\)
= \(\sqrt{22500+40000}\)
= \(\sqrt{62500}\) = 250 m.