(c) 60 km/hr
Let the speeds of the two trains be x m/s and 2x m/s respectively.
Since both the trains are moving in opposite directions, their relative speed = (x + 2x) m/s = 3x m/s
Given, \(\frac{110\,m+100\,m}{3x}=8\)
⇒ \(x\) = \(\frac{200}{24}\) m/s = \(\bigg(\frac{200}{24}\times\frac{18}{5}\bigg)\) km/hr = 30 km/hr
∴ Speed of the faster train = 60 km/hr.