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in Distance, Time and Speed by (49.2k points)
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Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is 

(a) 1 : 3 

(b) 3 : 2 

(c) 3 : 4 

(d) 1 : 2

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(b) 3 : 2

Let the speeds of the two trains be x m/s and y m/s respectively. 

∴ Length of the first train = 27x m and length of the second train = 17y m 

Since the trains are moving in opposite directions. 

Relative speed = (x + y) m/s

∴ \(\frac{27x+17y}{x+y} = 23\)       ⇒ 27x + 17y = 23x + 23y

⇒ 4x = 6y ⇒ \(\frac{x}{y}= \frac32.\)

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