The locus of the point P which moves such that P is at equidistance from their coordinate axes is: (a) y = 1/x (b) y = -x (c) y = x

Question

The locus of the point P which moves such that P is at equidistance from their coordinate axes is: 

(a) y = \(\frac{1}{x}\)

(b) y = -x 

(c) y = x 

(d) y = \(\frac{-1}{x}\)

Answer 1

(c) y = x

Given PA = PB 

y₁ = x₁ 

∴ Locus is y = x