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in Analytical Geometry by (47.4k points)
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The equation of the circle with centre (3, -4) and touches the x-axis is: 

(a) (x – 3)2 + (y – 4)2 = 4 

(b) (x – 3)2 + (y + 4)2 = 16 

(c) (x – 3)2 + (y – 4)2 = 16 

(d) x2 + y2 = 16

1 Answer

+1 vote
by (47.8k points)
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Best answer

(b) (x – 3)2 + (y + 4)2 = 16

Centre (3, -4). 

It touches the x-axis. 

The absolute value of y-coordinate is the radius, i.e., radius = 4. 

Equation is (x – 3)2 + (y + 4)2 = 16

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