(c) 8 : 3
Let the distance covered in one direction be x km.
Then, speed upstream = \(\frac{x}{\frac{44}{5}}\) km/hr
(8 hrs 48 min = \(8\frac{48}{60}=8\frac45\) hrs) = \(\frac{5x}{44}\) km/hr
Speed downstream =\(\frac{x}4\) km/hr
∴ Speed of boat in still water = \(\frac12\bigg(\frac{5x}{44}+\frac{x}{4}\bigg)\)
= \(\frac{8x}{44} = \frac{2x}{11}\) km/hr
Speed of current = \(\frac12\bigg(\frac{x}{4}-\frac{5x}{44}\bigg)=\frac{3x}{44}\) km/hr
∴ Required ratio = \(\frac{2x}{11}:\frac{3x}{44}=8:3.\)