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Solve 5 (2x + 1) ≤ 35, where x is a natural number

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Solve 5 (2x + 1) ≤ 35, where x is a natural number.

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5(2x + 1) ≤ 35 ⇒ 2x + 1 ≤ \(\frac{35}{5}\) ⇒ 2x + 1 ≤ 7 ≤ 2x ≤ 6 ⇒ x ≤ 3 

Since x ∈ N , the solution set = {1, 2, 3}.

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