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Find the values of the following: 

(i) cosec 15° 

(ii) sin (-105°) 

(iii) cot 75°

1 Answer

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(i) cosec 15° = \(\frac{1}{sin\,15°}\)

Consider sin 15° = sin(45° – 30°)

= sin 45° cos 30° – cos 45° sin 30°

cosec 15° = \(\frac{1}{sin\,15°}\) = \(\frac{2\sqrt{2}}{\sqrt{3}-1}\)

(ii) sin (-105°) = -sin (105°) (∵ sin (-θ) 

= – sin θ) = -[sin(60° + 45°)] 

= -[sin 60° cos 45° + cos 60° sin 45°]

(iii) cot 75° = \(\frac{1}{tan\,75°}\)

Consider tan 75° = tan (30° + 45°)

cot 75° = \(\frac{1}{tan\,75°}\) = \(\frac{\sqrt{3}-1}{\sqrt{3}+1}\)

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