Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.1k views
in Commercial Mathematics by (49.2k points)
closed by

Two pipes A and B can fill a tank in 15 hours and 30 hours respectively, while a third pipe C can empty the full tank in 25 hours. All the three pipes are opened in the beginning. After 10 hours, C is closed. In how much time will the tank be full?

1 Answer

+1 vote
by (53.1k points)
selected by
 
Best answer

Part of the tank filled when all the three pipes are opened for 10 hours

= 10 x \(\big(\frac{1}{15}+\frac{1}{20}-\frac{1}{25}\big)\) = 10 x \(\big(\frac{200+150-120}{300}\big)\) = \(\frac{230}{300}\) = \(\frac{23}{30}\)

Remaining empty part = 1 - \(\frac{23}{30}\) = \(\frac{7}{30}\)

Part of the tank filled in 1 hour by pipes (A and B) = \(\frac{1}{15}\) + \(\frac{1}{20}\) = \(\frac{4+3}{60}\) = \(\frac{7}{60}\)

\(\because\) \(\frac{7}{60}\) part is filled in 1 hour

\(\frac{7}{30}\) part is filled in 2 hours

\(\therefore\) Total time to fill the tank = 10 + 2 = 12 hours

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...