(a) 1 hour 15 min
Part of the tank emptied in 1 hour
= 1 - \(\big(\frac{1}{3}+\frac{4}{15}\big)\) = 1 - \(\frac{9}{15}\) = \(\frac{6}{15}\) = \(\frac{2}{5}\)
Time taken to empty the full tank = \(\frac{1}{\frac{2}{5}}\) = \(\frac{5}{2}\) hours
\(\therefore\) Time taken to empty the exactly half filled tank = \(\frac{1}{2}\times\frac{5}{2}\) hours = 1 hr 15 min.