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in Commercial Mathematics by (49.2k points)
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A large tanker can be filled by two pipes A and B in 60 minutes and 40 minutes respectively. How many minutes will it take to fill the tanker from empty state if B is used for half the time and A and B fill it for the other half? 

(a) 15 minutes 

(b) 20 minutes 

(c) 27.5 minutes 

(d) 30 minutes

1 Answer

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Best answer

(d) 30 minutes

Let the total time taken to fill the tank be x minutes.Then,

work by B in half hour + work done by (A + B) in half hour = 1

\(\big(\frac{1}{40}\times\frac{X}{2}\big)\) + \(\big(\frac{1}{60}+\frac{1}{40}\big)\) x \(\frac{X}{2}\) = 1

\(\Rightarrow\) \(\frac{X}{80}\) + \(\frac{X}{48}\) = 1  \(\Rightarrow\) \(\frac{3X+5X}{240}\) = 1

\(\Rightarrow\) 8x = 240 \(\Rightarrow\) x = 30 min.

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