(c) 40 min
Let one pipe take x minutes to fill the tank, then the other will take (x + 20) minutes.
Given, \(\frac{1}{X}+\frac{1}{X+20}\) = \(\frac{1}{24}\)
\(\Rightarrow\) \(\frac{X+20+X}{X^2+20X}\)= \(\frac{1}{24}\) \(\Rightarrow\) (2x + 20)24 = x2 + 20x
\(\Rightarrow\) x2 – 28x – 480 = 0 \(\Rightarrow\) x 2 – 40x + 12x – 480 = 0
\(\Rightarrow\) x(x – 40) + 12(x – 40) = 0
\(\Rightarrow\) (x – 40) (x +12) = 0
\(\Rightarrow\) x = 40 or –12
Neglecting negative values x = 40 min