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+1 vote
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in Quadratic Equations by (46.1k points)
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In a flight of 2800 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 100 km/hour and time increased by 30 minutes. Find the original duration of flight.

1 Answer

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Best answer

Let the original speed = x km/hr

∴ Normal time of flight = \(\frac{2800}{x}\) hours

∴ Time of flight, when speed is reduced = \(\frac{2800}{(x-100)}\) hours

According to the given condition, \(\frac{2800}{(x-100)}-\)\(\frac{2800}{x}\) = \(\frac{30}{60}=\frac12\)

Neglecting the –ve value. 

Original speed of the air craft = 800 km/hr

Original duration of flight = \(\frac{2800}{800} = 3\frac12\) hours.

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