The value of sin 15° is: (a) (√3 + 1)/2√2 (b) (√3 - 1)/2√2 (c) √3/√2

Question

The value of sin 15° is: 

(a) \(\frac{\sqrt{3}+1}{2\sqrt{2}}\)

(b) \(\frac{\sqrt{3}-1}{2\sqrt{2}}\)

(c) \(\frac{\sqrt{3}}{\sqrt{2}}\)

(d) \(\frac{\sqrt{3}}{2\sqrt{2}}\)

Answer 1

(b) \(\frac{\sqrt{3}-1}{2\sqrt{2}}\)

sin 15° = sin(45° – 30°) 

= sin 45° cos 30° – cos 45° sin 30°