Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
6.8k views
in Trigonometry by (47.9k points)
closed by

The value of sin 28° cos 17° + cos 28° sin 17° 

(a) \(\frac{1}{\sqrt{2}}\)

(b) 1 

(c) \(\frac{-1}{\sqrt{2}}\)

(d) 0

1 Answer

+1 vote
by (47.6k points)
selected by
 
Best answer

(a) \(\frac{1}{\sqrt{2}}\)

sin 28° cos 17° + cos 28° sin 17° = sin(28° + 17°) 

This is of the form sin(A + B), A = 28°, B = 17° 

= sin 45°

\(\frac{1}{\sqrt{2}}\)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...