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in Trigonometry by (47.9k points)
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The value of \(\frac{2tan30°}{1+tan^230°}\) is: 

(a) \(\frac{1}{2}\)

(b) \(\frac{1}{\sqrt{3}}\)

(c) \(\frac{\sqrt3}{2}\)

(d) √3

1 Answer

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Best answer

(d) √3

We know that sin 2A = \(\frac{2tanA}{1+tan^2A}\)

\(\frac{2tan30°}{1+tan^230°}\) = sin(2 x 30°) = sin 60° = \(\frac{\sqrt{3}}{2}\)

= tan 2A 

= tan 60° 

= √3

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