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in Quadratic Equations by (46.3k points)
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If the price of an article is increased by Rs 2 per dozen than at present, the number of things available for Rs 56 is 8 less than before. The price per dozen at present is : 

(a) Rs 14 

(b) Rs 12 

(c) Rs 10 

(d) Rs 28

1 Answer

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Best answer

(b) Rs 12

Let the present price be Rs k per dozen.

∴ Price per unit = Rs \(\frac{k}{12}\)

∴ Increased price = Rs (k +2) per dozen

∴ Increase price per unit = Rs \(\frac{(k+2)}{12}\)

Given, \(\frac{56}{\frac{k}{12}}-\frac{56}{\frac{(k +2)}{12}} = 8\)

⇒ \(\frac{12\times56}{k}-\frac{12\times56}{k+2}=8\)

⇒ 672 x (k + 2) - 672k = 8k(k + 2)

⇒ 8k2 + 16k - 1344 = 0

⇒ k2 + 2k - 168 = 0 ⇒ (k + 14)(k - 12) = 0

⇒ k = 12

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