(d) 108 m2
Let the length of the field be x m
Then, width of the field = (x + 3)m
Then x2 + (x + 3)2 = 152 (pyth. Th.)
⇒ x2 + x2 + 6x + 9 = 225
⇒ 2x2 + 6x - 216 = 0
⇒ x2 +3x - 108 = 0
⇒ (x + 12 )(x - 9) = 0 ⇒ x = -12,9
∴ Rejecting the negative value, length = 9 m
∴ Width = 12 m
⇒ Area of the field = 12 m × 9 m = 108 m2.