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Which of the following is equal to 1 ?

(a) \(\frac{(0.11)^2}{(1.1)^2\times0.1}\)

(b) \(\frac{(1.1)^2}{11^2\times(0.01)^2}\)

(c) \(\frac{(0.011)^2}{1.1^2\times0.012}\)

(d) \(\frac{(0.11)^2}{11^2\times0.01}\)

1 Answer

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Best answer

(c) \(\frac{(0.011)^2}{1.1^2\times0.012}\)

\(\frac{(0.11)^2}{(1.1)^2\times0.1}\) = \(\frac{0.0121}{1.21\times0.1} = \frac{0.0121}{0.121} = 0.1;\)

\(\frac{(1.1)^2}{11^2\times(0.01)^2}\) = \(\frac{1.21}{121\times0.0001} = \frac{0.01}{0.0001} = 100;\)

\(\frac{(0.011)^2}{1.1^2\times0.012}\) = \(\frac{0.000121}{1.21\times0.0001} = 1;\)

\(\frac{(0.11)^2}{11^2\times0.01}\) = \(\frac{0.0121}{121\times0.01} = \frac{0.0121}{1.21} = 0.01;\)

Hence, option (c) is the correct answer.

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