(c) \(\frac{(0.011)^2}{1.1^2\times0.012}\)
\(\frac{(0.11)^2}{(1.1)^2\times0.1}\) = \(\frac{0.0121}{1.21\times0.1} = \frac{0.0121}{0.121} = 0.1;\)
\(\frac{(1.1)^2}{11^2\times(0.01)^2}\) = \(\frac{1.21}{121\times0.0001} = \frac{0.01}{0.0001} = 100;\)
\(\frac{(0.011)^2}{1.1^2\times0.012}\) = \(\frac{0.000121}{1.21\times0.0001} = 1;\)
\(\frac{(0.11)^2}{11^2\times0.01}\) = \(\frac{0.0121}{121\times0.01} = \frac{0.0121}{1.21} = 0.01;\)
Hence, option (c) is the correct answer.