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Subtract 6a2 – 5ab + 3b2 from 4a2 – 3ab + b2.

1 Answer

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Best answer

(4a2 – 3ab+ b2) – (6a2– 5ab + 3b2)

= (4a2 – 6a2) + (- 3ab -(-5 ab)] + (b2– 3b2)

= (4 – 6) a2 + [-3ab + (+ 5ab)] + (1 – 3) b2

= [4 + (- 6)] a2 + (-3 + 5) ab + [1+ (-3)]b2

= -2a2 + 2ab – 2b2

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