(d) 2.5
Given exp.
= \(\frac{5.42+(6+24)}{(32.71)^2- (27.29)^2}÷\frac{(6.54)^2 - (3.46)^2}{3.08 \times(5+45)}\)
= \(\frac{5.42\times30}{(32.71+27.29)(32.71-27.29)}÷\frac{(6.54+3.46)(6.54-3.46)}{3.08\times50}\)
= \(\frac{5.42\times30}{60\times5.42}÷\frac{10\times3.08}{3.08\times50}\)
= \(\frac12÷\frac15=\frac52\) = 2.5.